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  5. pH Calculator

pH Calculator

Calculate pH of strong acids, weak acids, buffer solutions, and dilutions with step-by-step solutions. Includes pH converter, ICE tables, and Henderson-Hasselbalch equation. Perfect for GCSE and A-Level Chemistry.

pH Definition

pH measures hydrogen ion concentration

pOH Definition

pOH measures hydroxide ion concentration

pH + pOH Relationship

At 25°C, pH and pOH always sum to 14

Ionic Product of Water

At 25°C

Ka Expression

Acid dissociation constant

Henderson-Hasselbalch

For buffer solutions

Dilution Formula

Conservation of moles during dilution

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What is pH?

pH stands for "power of hydrogen" and measures how acidic or alkaline a solution is. It is defined as pH = -log₁₀[H⁺], where [H⁺] is the concentration of hydrogen ions in mol/dm³.

Because pH uses a logarithmic scale, each 1-unit change in pH represents a 10-fold change in hydrogen ion concentration. A solution with pH 3 has 10 times more H⁺ ions than one with pH 4, and 100 times more than pH 5.

At 25°C, the ionic product of water Kw = [H⁺][OH⁻] = 1.0 × 10⁻¹⁴. This means pH + pOH always equals 14. Pure water has pH = 7 (neutral), because [H⁺] = [OH⁻] = 1.0 × 10⁻⁷ mol/dm³.

The pH Scale

The pH scale runs from 0 (very acidic) through 7 (neutral) to 14 (very alkaline). Each substance in everyday life has a characteristic pH:

pH 1
Stomach acid
pH 3
Vinegar
pH 7
Pure water
pH 9
Baking soda
pH 13
Oven cleaner

Strong vs Weak Acids

Strong Acids

  • •Completely dissociate — every molecule releases H⁺
  • •[H⁺] = concentration (no Ka needed)
  • •Examples: HCl, HNO₃, H₂SO₄
  • •pH = -log₁₀[H⁺] directly

Weak Acids

  • •Partially dissociate — reach an equilibrium
  • •Need Ka and ICE table to find [H⁺]
  • •Examples: CH₃COOH, H₂CO₃, HF
  • •Ka = x²/(c − x), solve with quadratic

How to Calculate pH

Worked Example: 0.01 M HCl

  1. 1. HCl is a strong acid — fully dissociates
  2. 2. [H⁺] = 0.01 mol/dm³ (monoprotic, so [H⁺] = c)
  3. 3. pH = -log₁₀(0.01) = 2.00
  4. 4. pOH = 14 − 2 = 12.00, [OH⁻] = 1.0 × 10⁻¹² mol/dm³

Worked Example: 0.1 M NaOH

  1. 1. NaOH is a strong base — fully dissociates
  2. 2. [OH⁻] = 0.1 mol/dm³
  3. 3. pOH = -log₁₀(0.1) = 1.00
  4. 4. pH = 14 − 1 = 13.00

Worked Example: 0.1 M Ethanoic Acid (Ka = 1.8 × 10⁻⁵)

  1. 1. Set up ICE table: CH₃COOH ⇌ H⁺ + CH₃COO⁻
  2. 2. Ka = x²/(0.1 − x) = 1.8 × 10⁻⁵
  3. 3. Quadratic: x² + 1.8×10⁻⁵x − 1.8×10⁻⁶ = 0
  4. 4. x = [H⁺] = 1.33 × 10⁻³ mol/dm³
  5. 5. pH = -log₁₀(1.33 × 10⁻³) ≈ 2.87
  6. 6. % dissociation = (1.33 × 10⁻³ / 0.1) × 100 = 1.33%

Buffer Solutions

A buffer solution resists changes in pH when small amounts of acid or base are added. It contains a weak acid and its conjugate base (e.g. ethanoic acid + sodium ethanoate). The pH is calculated using the Henderson-Hasselbalch equation:

pH = pKa + log₁₀([A⁻]/[HA])

Worked Example: 0.1 M acid + 0.15 M conjugate base, Ka = 1.8 × 10⁻⁵

  1. 1. pKa = -log₁₀(1.8 × 10⁻⁵) = 4.74
  2. 2. pH = 4.74 + log₁₀(0.15/0.1) = 4.74 + 0.18 = 4.92
  3. 3. This is an acidic buffer (pH < 7) with more base than acid

The Dilution Equation

When you add water to an acid or base, the number of moles stays the same — only the concentration changes. The dilution equation C₁V₁ = C₂V₂ lets you calculate the new concentration or volume.

Worked Example: Dilute 25 cm³ of 0.1 M HCl to 100 cm³

  1. 1. C₁V₁ = C₂V₂ → 0.1 × 25 = C₂ × 100
  2. 2. C₂ = 2.5/100 = 0.025 mol/dm³
  3. 3. pH before: -log₁₀(0.1) = 1.00
  4. 4. pH after: -log₁₀(0.025) = 1.60
  5. 5. pH increased by 0.60 (solution became less acidic)

Common Mistakes

✗Using Ka for strong acids
✓Strong acids dissociate 100% — just use [H⁺] = concentration directly
✗Forgetting H₂SO₄ is diprotic
✓[H⁺] = 2 × concentration for sulfuric acid
✗Swapping pH and pOH
✓pH = -log₁₀[H⁺] for acids. Use pOH first for bases, then pH = 14 − pOH
✗Using 10^(+pH) instead of 10^(−pH)
✓[H⁺] = 10^(−pH). The minus sign in the exponent is critical!
✗Forgetting log in Henderson-Hasselbalch
✓pH = pKa + log₁₀([A⁻]/[HA]) — you need the logarithm, not just the ratio
✗Assuming pH is always 0–14
✓pH < 0 for concentrated strong acids (>1M) and pH > 14 for concentrated strong bases

Exam-Style Worked Examples

GCSE

Calculate the pH of 0.5 mol/dm³ HCl

HCl is a strong acid, so [H⁺] = 0.5 mol/dm³.
pH = -log₁₀(0.5) = 0.30

GCSE

A solution has pH 4. What is [H⁺]?

[H⁺] = 10⁻ᵖᴴ = 10⁻⁴ = 0.0001 mol/dm³ (or 1 × 10⁻⁴)

A-Level

Find pH of 0.05 M ammonia (Kb = 1.8 × 10⁻⁵)

ICE: Kb = x²/(0.05 − x). Using quadratic: x = [OH⁻] = 9.49 × 10⁻⁴.
pOH = -log₁₀(9.49 × 10⁻⁴) = 3.02.
pH = 14 − 3.02 = 10.98

A-Level

Buffer: 0.2 M CH₃COOH + 0.3 M CH₃COONa (Ka = 1.8 × 10⁻⁵)

pKa = -log₁₀(1.8 × 10⁻⁵) = 4.74.
pH = 4.74 + log₁₀(0.3/0.2) = 4.74 + 0.176 = 4.92

Frequently Asked Questions

What is pH?

pH = -log₁₀[H⁺]. It measures how acidic or alkaline a solution is on a scale typically from 0 to 14, where 7 is neutral.

How do you calculate pH of a strong acid?

For a strong acid: [H⁺] = concentration × proton count, then pH = -log₁₀[H⁺]. Strong acids dissociate completely.

What is the difference between strong and weak acids?

Strong acids dissociate 100% (HCl, HNO₃, H₂SO₄). Weak acids partially dissociate and have a Ka value (CH₃COOH, HF).

How do you use an ICE table?

ICE stands for Initial, Change, Equilibrium. Set up concentrations for each species, substitute into Ka expression, and solve for x.

What is the Henderson-Hasselbalch equation?

pH = pKa + log₁₀([A⁻]/[HA]). Used to calculate buffer pH from weak acid concentration, conjugate base concentration, and Ka.

Can pH be negative?

Yes! Any strong acid with concentration > 1 mol/dm³ gives pH < 0. For example, 10 M HCl has pH = -1.

What is Kw?

Kw = [H⁺][OH⁻] = 1.0 × 10⁻¹⁴ at 25°C. This is the ionic product of water and explains why pH + pOH = 14.

What does C₁V₁ = C₂V₂ mean?

The dilution equation. Moles are conserved: concentration × volume before = concentration × volume after.

What is percent dissociation?

% dissociation = ([H⁺] at equilibrium / initial concentration) × 100. It shows what fraction of a weak acid has dissociated.

Why is H₂SO₄ special?

H₂SO₄ is diprotic — it releases 2 H⁺ ions per molecule. So [H⁺] = 2 × concentration, giving a lower pH than HCl at the same concentration.

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